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求y=2sin²x-cos2x-1的最值
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求y=2sin²x-cos2x-1的最值
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答案和解析
y=2sin²x-cos2x-1
= 1- cos2x - cos2x -1
= -2cos2x
∵-1≤ cos2x ≤1
∴-2≤y≤2
最小值为 -2 ,最大值为2
= 1- cos2x - cos2x -1
= -2cos2x
∵-1≤ cos2x ≤1
∴-2≤y≤2
最小值为 -2 ,最大值为2
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