1.求函数y=sin(2x-π/3)的对称中心2.求函数y=sin(π/3-2x)的单调递增区间、对称轴

Question

1.求函数y=sin(2x-π/3)的对称中心
2.求函数y=sin(π/3-2x)的单调递增区间、对称轴

Answer 1

y=sin(2x-π/3) = 2sin(x-π/6) x-π/6=Kπ+π/2 x=Kπ+2/3π 对称轴
y=sin(π/3-2x) = 2sin(π/6-x) π/6-x=Kπ+π/2 x=-Kπ-1/3π 对称轴
单调递增区间：2Kπ-π/2《π/3-2x《2Kπ+π/2 -2Kπ+π/2》2x-π/3》-2Kπ-π/2
2Kπ+5π/6》2x》-2Kπ-π/6
-Kπ-π/12《x《Kπ+5π/12