早教吧作业答案频道 -->英语-->
.byhisexpression,hemusthavegot"A"intheexam.A)JudgingB)JudgedC)HavingbeenjudgedD)tobejudge
题目详情
.____by his expression,he must have got "A" in the exam.
A) Judging B) Judged C) Having been judged D)to be judge
A) Judging B) Judged C) Having been judged D)to be judge
▼优质解答
答案和解析
A) Judging
Judging by/from 根据…来判断 ,是固定搭配.
无论逻辑主语发不发出这个动作,都是用Judging这种形式.
Judging by/from 根据…来判断 ,是固定搭配.
无论逻辑主语发不发出这个动作,都是用Judging这种形式.
看了 .byhisexpressi...的网友还看了以下:
1.如果a≠0,p是正整数,那么下列各式中错误的是:()A.a^-p=1/a^pB.a^-p=(1/ 2020-03-30 …
求出下列各式中的字母a的取值范围:1.a<a/22.a<1/a3.|a|/a=-14.1/a>a>0 2020-03-30 …
1.a>0且a≠1①㏒a(1)+㏒a(a)②㏒a(a²)-aˆ㏒a(3)2.若6ˆa=8,求㏒6(4 2020-03-30 …
a=xa+a=a+x2a=a+x2a-2x=a+x-2x2(a-x)=a-x2=1到底a=xa+a= 2020-03-30 …
1.a≠0,b≠0,则a/|a|+b/|b|的不同取值的个数为()A.3B.2C.1D.02.若|x 2020-03-31 …
1.判断a、b、c能否构成三角形的三条边长的条件是().选项:a、a>0&&b>0&&c>0b、a+ 2020-03-31 …
1.Afromhisappearance,hewasreallyworkinghardatthat 2020-05-20 …
(a+1)(a^2+1)(a^4+1)(a^8+1)(a^16+1)=(a-1)[(a+1)(a^ 2020-05-22 …
.byhisexpression,hemusthavegot"A"intheexam.A)Judg 2020-06-02 …
递回关系式的运算公式(数列)以下是推导一个公式"a=a+r(1-p^n)/(1-p)"的过程a=p* 2021-01-13 …