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(1+2i)(x+yi)=4+3i(x-2y)+(y+2x)i=4+3i
题目详情
(1+2i)(x+yi)=4+3i (x-2y)+(y+2x)i=4+3i
▼优质解答
答案和解析
(1+2i)(x+yi)=4+3i
x+yi+2xi-2y=4+3i
(x-2y)+(y+2x)i=4+3i
所以x-2y=4 (实部相等)
y+2x=3 (虚部相等)
解得:x=2,y=-1
x+yi+2xi-2y=4+3i
(x-2y)+(y+2x)i=4+3i
所以x-2y=4 (实部相等)
y+2x=3 (虚部相等)
解得:x=2,y=-1
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