计算s=3!+5!+7!+……＋N!,求直到S＞＝680000为止的奇数N．

Question

计算s=3!+5!+7!+……＋N!,求直到S＞＝680000为止的奇数N．

Answer 1

unsigned long factorial(unsigned int n){ //求阶乘
if (n==1 || n==0) return 1;
else return n*factorial(n-1);
}
void main(){
long s=0;
int i=3;
while (s