（1）解分式方程：1x+1+2x−1=4x2−1（2）当x=3时，求（1x2−2x-1x2−4x+4）÷（2x2−2x）的值．

Question

（1）解分式方程：(1)/(x+1)+(2)/(x−1)=(4)/(x2−1)
（2）当x=3时，求（(1)/(x2−2x)-(1)/(x2−4x+4)）÷（(2)/(x2−2x)）的值．(1)/(x+1)+(2)/(x−1)=(4)/(x2−1)
（2）当x=3时，求（(1)/(x2−2x)-(1)/(x2−4x+4)）÷（(2)/(x2−2x)）的值．(1)/(x+1)11x+1x+1(2)/(x−1)=(4)/(x2−1)
（2）当x=3时，求（(1)/(x2−2x)-(1)/(x2−4x+4)）÷（(2)/(x2−2x)）的值．(2)/(x−1)22x−1x−1(4)/(x2−1)
（2）当x=3时，求（(1)/(x2−2x)-(1)/(x2−4x+4)）÷（(2)/(x2−2x)）的值．(4)/(x2−1)44x2−1x2−1x2−1x2−12−1
(1)/(x2−2x)-(1)/(x2−4x+4)）÷（(2)/(x2−2x)）的值．(1)/(x2−2x)11x2−2xx2−2xx2−2xx2−2x2−2x(1)/(x2−4x+4)）÷（(2)/(x2−2x)）的值．(1)/(x2−4x+4)11x2−4x+4x2−4x+4x2−4x+4x2−4x+42−4x+4(2)/(x2−2x)）的值．(2)/(x2−2x)22x2−2xx2−2xx2−2xx2−2x2−2x

Answer 1

（1）1x+1+2x−1=4x2−1方程两边同时乘以（x+1）（x-1）得  x-1+2（x+1）=4解这个整式方程得x=1经检验，x=1是増根，原方程无解．（2）（1x2−2x-1x2−4x+4）÷（2x2−2x）=[x−2x(x−2)2−xx(x−2)2]÷2x(...