如图所示，在四边形ABCD中，EF∥BC，FG∥AD，则EFBC+FGAD=．

Question

(EF)/(BC)+(FG)/(AD)=______．
(EF)/(BC)EFEFBCBC(FG)/(AD)FGFGADAD

Answer 1

∵EF∥BC，
∴(EF)/(BC)＝(AF)/(AC)
∵FG∥AD，
∴(FG)/(AD)＝(CF)/(AC)，
∴(EF)/(BC)+(FG)/(AD)=(AF)/(AC)+(CF)/(AC)=(AC)/(AC)＝1
故答案为：1 (EF)/(BC)EFEFEFBCBCBC＝(AF)/(AC)AFAFAFACACAC
∵FG∥AD，
∴(FG)/(AD)＝(CF)/(AC)，
∴(EF)/(BC)+(FG)/(AD)=(AF)/(AC)+(CF)/(AC)=(AC)/(AC)＝1
故答案为：1 (FG)/(AD)FGFGFGADADAD＝(CF)/(AC)CFCFCFACACAC，
∴(EF)/(BC)+(FG)/(AD)=(AF)/(AC)+(CF)/(AC)=(AC)/(AC)＝1
故答案为：1 (EF)/(BC)EFEFEFBCBCBC+(FG)/(AD)FGFGFGADADAD=(AF)/(AC)+(CF)/(AC)=(AC)/(AC)＝1
故答案为：1 (AF)/(AC)AFAFAFACACAC+(CF)/(AC)CFCFCFACACAC=(AC)/(AC)＝1
故答案为：1 (AC)/(AC)ACACACACACAC＝1
故答案为：1