因式分解：x4-2x4y+x4y2-2x2+y2-2x2y2+2y+1

Question

因式分解：x4-2x4y+x4y2-2x2+y2-2x2y2+2y+1

Answer 1

x4-2x4y+x4y2-2x2+y2-2x2y2+2y+1=x4(y-1)(y-1)-x2(y+1)(y-1)+(y+1)(y+1)-x2(y+1)(y-1)=[x4(y-1)-x2(y+1)]+(y+1)[(y+1)-x2(y-1)]=[(y+1)-x2(y-1)]2
最后一步没细写,不过如果楼主看不出来的话就太失败了