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求y=ln(1+√x)/(1-√x)的导数

题目详情
求y=ln(1+√x)/(1-√x)的导数
▼优质解答
答案和解析
y′
=[(1-√x)/(1+√x)][(1+√x)/(1-√x)]′
=[(1-√x)/(1+√x)]{[(1+√x)′(1-√x)-(1+√x)(1-√x)′]/(1-√x)^2}
=[1/(1-x)][(1+√x)′(1-√x)-(1+√x)(1-√x)′]
=[1/(1-x)][(1/2)(1-√x)/√x+(1/2)(1+√x)/√x]
=[1/(1-x)]/√x
=√x/(x-x^2)