现有两个不同的char型变量,取值为年月（yyyymm）,要写一个循环取出他们之间的取值,例如：char1=‘201110’；char2=‘201203’；取出for循环取值分别为201110201111201112201201201202201203用C++

Question

现有两个不同的char型变量,取值为年月（yyyymm）,要写一个循环取出他们之间的取值,例如：char1 = ‘201110’； char2 = ‘201203’； 取出 for循环取值分别为 201110 201111 201112 201201 201202 201203
用C++

Answer 1

基本上是用C写的,子函数改下try..catch那部分,就可以用C编译了.
生成的字符串是用空格分开的,单个使用的话用strtok就行了.
#include
#include
#include
using namespace std;
char* getInnerDate(char *char1,char *char2)
{
char *p1,*p2,*sRet,*pRet;
int yy1,mm1,yy2,mm2,mm,m,y;
char buff[10];
// Swap date string order.
if( strcmp(char2,char1) >= 0){
p1 = char1;
p2 = char2;
}else{
p1 = char2;
p2 = char1;
}
// Translate to year & month.
try{
strncpy(buff,p1,6);
buff[6] = 0;
mm1 = atoi(&buff[4]);
buff[4] = 0;
yy1 = atoi(buff);
strncpy(buff,p2,6);
buff[6] = 0;
mm2 = atoi(&buff[4]);
buff[4] = 0;
yy2 = atoi(buff);
}catch(...){
return NULL;
}
// Total months between 2 date strings.
mm2 += (yy2 - yy1) * 12 + 1;
sRet = (char*)malloc((mm2*7 + 1)*sizeof(char));
if(NULL != sRet){
pRet = sRet;
y = yy1;
m = mm1;
for(int mm=mm1; mm 12){
m -= 12;
y ++;
}
sprintf(pRet,"%04d%02d ",y,m);
m++;
pRet += 7;
}
}
return sRet;
}
int main(void)
{
char char1[]="201110",char2[]="201203";
char *p;
if(NULL != (p = getInnerDate(char1,char2))){
cout