早教吧作业答案频道 -->英语-->
Nosmoking(allow).ifyouarediscovered,you(fine)还有一条Cheatingbyathletes(notexcuse).they(tell)toleaveand(punish)
题目详情
No smoking ____________(allow).if you are discovered ,you____________(fine )
还有一条Cheating by athletes ________________(not excuse).they_______________(tell)to leave and ___________(punish)
还有一条Cheating by athletes ________________(not excuse).they_______________(tell)to leave and ___________(punish)
▼优质解答
答案和解析
答案是:1. is allowed. will be fined.2. will not be excused.will be told.to be punished .3、are not allowed . will be taken away.
看了 Nosmoking(allo...的网友还看了以下:
don"t punish a dog one time and not the next time 2020-05-14 …
matlab 求解二元非线性方程组本人初次接触MATLAB,望大虾赐教!r=r0*((tsa-t) 2020-05-16 …
n阶方阵A对任意n维向量x,满足x^TAx=0,充要条件为AT=-A;证明:充分性:f=x^TAx 2020-05-17 …
r(A*A^T)=r(A^T*A)=r(A)证明方程AX=0与A^TAX=0同解AX=0显然有A^ 2020-06-10 …
.请教A+B=A(B^T)B+A(A^T)B能写成A+B=AB(B^T)+(A^T)AB.请教A+ 2020-06-12 …
设n阶矩阵A=E-a*a^T,其中a是n维非零列向量,证明1.A^2=A的充要条件是a^T*a设n 2020-06-23 …
关于矩阵?设A为n阶可逆矩阵,下列()恒正确?A.(2A)^T=2A^TB.(2A)^-1=2A^ 2020-07-11 …
已知向量a≠e,|e|=1,满足:任意t∈R.已知向量a不等于e,|e|=1,对任意t属于R,恒有 2020-07-25 …
有关极限的算法a^t-b^t/t如何能化简出答案为lna/b.a^t-b^t/t如何能化简出答案为 2020-07-30 …
对于积分上限函数∫(a,t)f(y)dy,知道被积函数是f(t).那么对于∫(a,t)f(x+y) 2020-08-02 …