怎么做呢.过程要详细啊,详细设函数f(x)=3sin(ωx+π/6),ω>0,x∈(-∞,+∞),且以2/π为最小正周期.1.求f(0)2.求f(x)的解析式3.已知f(α/4+π/12)=9/5

Question

怎么做呢.过程要详细啊,详细
设函数f(x)=3sin(ωx+π/6),ω>0,x∈(-∞,+∞),且以2/π为最小正周期.
1.求f(0)
2.求f(x)的解析式
3.已知f(α/4+π/12)=9/5

Answer 1

1.f(0) )=3sin(π/6) = 3 * (1/2) = 3/2
2.以π/2为最小正周期,2π / ω = π/2,则 ω=4
3.f(α/4+π/12) = 3 sin(α +π/3 +π/6) = 3 sin(α +π/2) = 9/5,
cosα = - sin(α +π/2) = -3/5