早教吧作业答案频道 -->数学-->
在matalb中对于反三角函数进行符号积分>>symsx>>int(x*log(x^4)*asin(1/(x^2)),x,1,3)Warning:Explicitintegralcouldnotbefound.ans=int(x*asin(1/x^2)*log(x^4),x=1..3)
题目详情
在matalb中对于反三角函数进行符号积分
>> syms x
>> int(x*log(x^4)*asin(1/(x^2)),x,1,3)
Warning:Explicit integral could not be
found.
ans =
int(x*asin(1/x^2)*log(x^4),x = 1..3)
>> syms x
>> int(x*log(x^4)*asin(1/(x^2)),x,1,3)
Warning:Explicit integral could not be
found.
ans =
int(x*asin(1/x^2)*log(x^4),x = 1..3)
▼优质解答
答案和解析
--- help for filtstates/int.m ---
INT Convert a FILTSTATES.CIC object to an integer matrix.
INT(Hs) returns an signed integer matrix for the FILTSTATES.CIC
object.
EXAMPLE:
Hm = mfilt.cicdecim;
hs = Hm.states; % Returns a FILTSTATES.CIC object
states = int(hs); % Convert object to a signed integer matrix.
int(***):就是把括号里的转化成整型类型.
int(x*asin(1/x^2)*log(x^4),x = 1..3):该函数得到结果后,把结果变成整型,如果计算得到3.5,那么输出的是3
INT Convert a FILTSTATES.CIC object to an integer matrix.
INT(Hs) returns an signed integer matrix for the FILTSTATES.CIC
object.
EXAMPLE:
Hm = mfilt.cicdecim;
hs = Hm.states; % Returns a FILTSTATES.CIC object
states = int(hs); % Convert object to a signed integer matrix.
int(***):就是把括号里的转化成整型类型.
int(x*asin(1/x^2)*log(x^4),x = 1..3):该函数得到结果后,把结果变成整型,如果计算得到3.5,那么输出的是3
看了 在matalb中对于反三角函...的网友还看了以下:
值域:y=x^2-x/x^2-x+1要用分离常数法!y=(x^2-x)/(x^2-x+1)=(x^ 2020-04-09 …
已知a>1,设命题P:a(x-2)+1>0,命题Q(x-1)^2>a(x-2)+1.求使得P,Q都 2020-05-15 …
x趋向于1时f(x)=(x^2-1)/(x-1)的极限为什么等于0我做的是limx→1(x^2-1 2020-05-16 …
(1)2x^2+3x-1(2)x^3-8y^3-z^3-6xyz(3)x^3-9x+8(4)x^9 2020-05-17 …
1.已知函数f(x)满足f(x)+2f(1/x)=2x-1,求f(x)2.设f(x)是定义在R上的 2020-05-23 …
自学到有理函数的积分,但看不懂有些步骤怎么分的?(x^2+1)/x(x-1)^2=A/x+B/(x 2020-06-05 …
设f(x)在(-∞,+∞)内可导,且F(x)=f(x^2-1)+f(1-x^2),证明F'(1)= 2020-06-15 …
大家帮我看看这个函数的定义域是什么,f(x)=[(x^2)-1]/x-1 的定义域到底是以下哪一个 2020-06-27 …
lim(x→1)时x^2+1/x-1有极限吗?并说出为什么有或没有如题,有人说没有,因为分子里没有 2020-07-04 …
解:(1)f(x+1)=f(x)-f(x-1)=[f(x-1)-f(x-2)]-f(x-1)=-f 2020-07-19 …