早教吧作业答案频道 -->英语-->
英语翻译Packaging&MarketingLicense”means薬品补充申请批件(inChinese)forBulkandProduct,thelicensewhichisrequiredtobeissuedbytheStateFoodandDrugAdministrationforpackagingofBulkintoProductinTerritory,anddist
题目详情
英语翻译
Packaging & Marketing License” means薬品补充申请批件 (in Chinese) for Bulk and Product,the license which is required to be issued by the State Food and Drug Administration for packaging of Bulk into Product in Territory,and distribution,promotion and sale of Product in Territory.
Packaging & Marketing License” means薬品补充申请批件 (in Chinese) for Bulk and Product,the license which is required to be issued by the State Food and Drug Administration for packaging of Bulk into Product in Territory,and distribution,promotion and sale of Product in Territory.
▼优质解答
答案和解析
在中文里的意思是{药品补充申请批件},
看了 英语翻译Packaging&...的网友还看了以下:
f(x1)f(x2)+g(x1)g(x2)=g(x1-x2),求证[f(x)]^n+[g(x)]^ 2020-05-17 …
(2013•眉山二模)如图所示,f(x)是定义在区间[-c,c](c>0)上的奇函数,令g(x)= 2020-06-09 …
一个关于群论的问题,拉格朗日定理是有穷群的子群的元数是这群的元数的因数,即|G|=|H|*|G:H 2020-06-22 …
(2014•四川)在10L恒容密闭容器中充入X(g)和Y(g),发生反应X(g)+Y(g)⇌M(g 2020-06-23 …
对大于0的自然数n规定一种运算“G”:①当n是奇数时,G(n)=3n+1;②当n是偶数时,G(n) 2020-07-22 …
已知f(n)=1+123+133+143+…+1n3,g(n)=32-12n2,n∈N*.(1)当 2020-07-22 …
“设f(n)=1+1/2+1/3+1/4+……+1/n,是否存在关于自然数n的函数g(n)使f(1 2020-08-01 …
极限的问题若f(n)、g(n)分别是关于n的一元多项式,f(n)=apn^p+a(p-1)n^(p 2020-08-03 …
已知f(x)=bx+1为x的一次函数,b为不等于1的常数,且g(n)=1(n=0)f[g(n-1)] 2020-11-17 …
如果函数g(x)满足:对任意实数m,n均有g(mn+1)-g(m)g(n)=2-g(n)-m成立,那 2021-02-04 …