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(2014•南通模拟)设数列{an},a1=1,an+1=an3+13n.数列{bn},bn=3n-1an.正数数列{dn},dn2=1+1bn2+1bn+12.(1)求证:数列{bn}为等差数列;(2)设数列{bn},{dn}的前n项和分别为Bn,Dn,求数列{bnDn+dnBn-

题目详情
(2014•南通模拟)设数列{an},a1=1,an+1=
an
3
+
1
3n
.数列{bn},bn=3n-1an.正数数列{dn},dn2=1+
1
bn2
+
1
bn+12

(1)求证:数列{bn}为等差数列;
(2)设数列{bn},{dn}的前n项和分别为Bn,Dn,求数列{bnDn+dnBn-bndn}的前n项和Sn
▼优质解答
答案和解析
(1)由an+1=an3+13n.得3nan+1=3n−1an+1.又bn=3n-1an,所以bn+1=bn+1,又b1=a1=1,所以数列{bn}是以1为首项,1为公差的等差数列.(2)由(1)得bn=1+(n-1)×1=n,Bn=n(n+1)2,因为dn2=1+1bn2+1bn+12.所以dn2...