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cos(6分之19π)tan(-3分之16π)化成π的形式,
题目详情
cos(6分之19π)tan(-3分之16π)
化成π的形式,
化成π的形式,
▼优质解答
答案和解析
cos(19π/6)tan(-16π/3)
=cos(12π/6+7π/6)[-tan(16π/3)]
=-cos(7π/6) tan(12π/3+4π/3)
=-cos(π+π/6) tan(π+π/3)
=-(-cosπ/6)*tanπ/3
=√3/2*√3
=3/2
=cos(12π/6+7π/6)[-tan(16π/3)]
=-cos(7π/6) tan(12π/3+4π/3)
=-cos(π+π/6) tan(π+π/3)
=-(-cosπ/6)*tanπ/3
=√3/2*√3
=3/2
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