早教吧作业答案频道 -->英语-->
英语翻译Theworkerbeeofthefloralcrowns,thesegorgeousmid-sizedsedansarenothingshortofjuuuuuustriiiight.Toyingwithmoregenerousbloomsizes,alongwithheavieramountsoffiller,thesearen’tyoureasilymissedaccentpieces.Wearing
题目详情
英语翻译
The worker bee of the floral crowns,these gorgeous mid-sized sedans are nothing short of juuuuuust riiiight.Toying with more generous bloom sizes,along with heavier amounts of filler,these aren’t your easily missed accent pieces.Wearing a floral crown of this type & size shows your truly committed to your floral crown look and it is a key player in the look your trying to convey.These beauties allow for more full size blooms to be a true star even allowing elements that are typically understated to shine as a larger group together.The mid-size crown,she is a keeper!
The worker bee of the floral crowns,these gorgeous mid-sized sedans are nothing short of juuuuuust riiiight.Toying with more generous bloom sizes,along with heavier amounts of filler,these aren’t your easily missed accent pieces.Wearing a floral crown of this type & size shows your truly committed to your floral crown look and it is a key player in the look your trying to convey.These beauties allow for more full size blooms to be a true star even allowing elements that are typically understated to shine as a larger group together.The mid-size crown,she is a keeper!
▼优质解答
答案和解析
花冠上的工蜂,这些鲜艳的中等大小的花轿戴在头上简直正合适!把玩着这款具有更丰富的花朵尺寸,更重的填充物,这些都是你不能轻易错过的地方!戴上这款花冠,展现你对花冠装饰的喜爱,它将会是传达你形象的重要角色.这些魅力能让更多全开的花脱颖而出,甚至让一些轻描淡写的元素在一个更大的花群中一起闪耀.这款中等大小的花冠,简直就是一个园艺师!
看了 英语翻译Theworkerb...的网友还看了以下:
已知函数f(x)=sin(2x+φ)(φ∈R),若f(x)≤|f(π6)|对x∈R恒成立,且f(π 2020-04-12 …
已知K(xa-x2)^2≤(x1-x2)(f(x1)-f(x2))和∣f(x1)-f(x2)∣≤∣ 2020-05-17 …
f(x)=e^x-kx,设函数F(x)=f(x)+f(-x),求证F(1)F(2)……F(n)>[ 2020-05-21 …
定义在R上的函数f(x)对任意a,b∈R都有f(a+b)=f(a)+f(b)+k(k为常数).(I 2020-06-02 …
若曲线y=f(x)按向量(hk)平移,则平移后的曲线为()??A.y=f(x-h)-k??B.y= 2020-07-09 …
函数f(x)满足条件1.a≤f(x)≤b,对于任意的x∈[a,b];2.存在常数k,使得对于任意的 2020-07-26 …
三元一次方程组a*x+b*y+c*z+d=0,e*x+f*y+g*z+h=0,i*x+j*y+k* 2020-08-03 …
f(x)在[a,b]上连续(a,b)上可导,且f(a)=f(b)=0证明任取k属于R,存在ξ属于(a 2020-11-03 …
一元二次方程根的分布情况,如下,1.两根都大于k:的塔>=o,-b/2a>k,f(k)>o2.两根都 2020-11-12 …
设函数f(x)=(x-1)kcosx(k∈N*),则()A.当k=2013时,f(x)在x=1处取得 2020-12-08 …