早教吧作业答案频道 -->其他-->
（23-47）×21+44=(45+14)÷72−110=1-[1-（1-23÷23）]×34+5=[47×(35−14)+310]÷12=(14−110÷2)×513+1÷1312=56+19−23=
题目详情
（
| (
| ||||||||||||||||
1-[1-（1-
| [
| ||||||||||||||||
(
|
|
（
| (
| ||||||||||||||||
1-[1-（1-
| [
| ||||||||||||||||
(
|
|
| 2 |
| 3 |
| 4 |
| 7 |
| 4 |
| 4 |
| 4 |
| 5 |
| 1 |
| 4 |
| 7 |
| 2 |
| 1 |
| 10 |
| 2 |
| 3 |
| 4 |
| 7 |
| 4 |
| 4 |
| 2 |
| 3 |
| 4 |
| 7 |
| 4 |
| 4 |
| 2 |
| 3 |
| 4 |
| 7 |
| 4 |
| 4 |
| 4 |
| 7 |
| 4 |
| 4 |
| 4 |
| 4 |
| 4 |
| 5 |
| 1 |
| 4 |
| 7 |
| 2 |
| 1 |
| 10 |
| 4 |
| 5 |
| 1 |
| 4 |
| 7 |
| 2 |
| 1 |
| 10 |
| 4 |
| 5 |
| 1 |
| 4 |
| 7 |
| 2 |
| 1 |
| 10 |
| 2 |
| 3 |
| 2 |
| 3 |
| 3 |
| 4 |
| 4 |
| 7 |
| 3 |
| 5 |
| 1 |
| 4 |
| 3 |
| 10 |
| 1 |
| 2 |
| 2 |
| 3 |
| 2 |
| 3 |
| 3 |
| 4 |
| 2 |
| 3 |
| 2 |
| 3 |
| 3 |
| 4 |
| 2 |
| 3 |
| 2 |
| 3 |
| 3 |
| 4 |
| 2 |
| 3 |
| 3 |
| 4 |
| 3 |
| 4 |
| 4 |
| 7 |
| 3 |
| 5 |
| 1 |
| 4 |
| 3 |
| 10 |
| 1 |
| 2 |
| 4 |
| 7 |
| 3 |
| 5 |
| 1 |
| 4 |
| 3 |
| 10 |
| 1 |
| 2 |
| 4 |
| 7 |
| 3 |
| 5 |
| 1 |
| 4 |
| 3 |
| 10 |
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 10 |
| 5 |
| 13 |
| 13 |
| 12 |
| 5 |
| 6 |
| 1 |
| 9 |
| 2 |
| 3 |
| 1 |
| 4 |
| 1 |
| 10 |
| 5 |
| 13 |
| 13 |
| 12 |
| 1 |
| 4 |
| 1 |
| 10 |
| 5 |
| 13 |
| 13 |
| 12 |
| 1 |
| 4 |
| 1 |
| 10 |
| 5 |
| 13 |
| 13 |
| 12 |
| 5 |
| 6 |
| 1 |
| 9 |
| 2 |
| 3 |
| 5 |
| 6 |
| 1 |
| 9 |
| 2 |
| 3 |
| 5 |
| 6 |
| 1 |
| 9 |
| 2 |
| 3 |
▼优质解答
答案和解析
（1）（23-47）×21+44，=23×21-47×21+1，=14-12+1，=3；（2）(45+14)÷72−110，=2120÷72-110，=0.3-0.1，=0.2；（3）1-[1-（1-23÷23）]×34+5，=1-[1-（1-1）]×34+5，=1-[1-0]×34+5，=1×34+5，=5.75；（4）...
看了 （23-47）×21+44=...的网友还看了以下：
S=(1+1/1*2+(2+1/2*3)+(3+1/3*4)+...+(20+1/20*21)S= 2020-04-27 …
上面写不下,我写在下面填符号1.(1)1/2(）0.4()3/10()0.1=1(2)1/2()0 2020-05-13 …
数列{an}各项是1或3,且在第k个1和第k＋1个1之间有2k-1个3,即1,3,1,3,3,3, 2020-05-16 …
谁能告诉我这个算式的简化公式(1+x)(1+x^2)(1+x^3)(1+x^4)(1+x^5)(1 2020-05-17 …
1+2+3+n=2分之1n(n+1),n是正整数,研究1*2+2*3+你(n+1),观察1*2=3 2020-05-20 …
天才进1,1,2,1,2,1,2,3,3,1,3,2,1,2,3,3,1,3,2,1,3,2,3, 2020-05-21 …
49.7-[-23/3/4+(18.7-25.25)]12+1又3/4-8又5/12-6.75-( 2020-06-04 …
已知1^3=1=1/4*1^2*2；1^3+2^3=9=1/4*2^2*3^2；1^3+2^3+3 2020-07-19 …
虚数化简1/4*(-4+4*i*3^(1/2))^(1/3)+1/(-4+4*i*3^(1/2)) 2020-07-30 …
观察下列各式：1^3+2^3=1+8=9,而(1+2)^2=9……观察下列各式：1^3+2^3=1+ 2021-01-01 …