解下列分式方程．（1）1x−3=2+x3−x；（2）1x+1+2x−1=4x2−1．

Question

(1)/(x−3)=2+(x)/(3−x)；                  
（2）(1)/(x+1)+(2)/(x−1)=(4)/(x2−1)．(1)/(x−3)11x−3x−3(x)/(3−x)；                  
（2）(1)/(x+1)+(2)/(x−1)=(4)/(x2−1)．(x)/(3−x)xx3−x3−x
(1)/(x+1)+(2)/(x−1)=(4)/(x2−1)．(1)/(x+1)11x+1x+1(2)/(x−1)=(4)/(x2−1)．(2)/(x−1)22x−1x−1(4)/(x2−1)．(4)/(x2−1)44x2−1x2−1x2−1x2−12−1

Answer 1

（1）去分母得：1=2x-6-x，
移项合并得：x=7，
经检验x=7是分式方程的解；
（2）去分母得：x-1+2x+2=4，
移项合并得：3x=3，
解得：x=1，
经检验x=1是增根，分式方程无解．