1.(x^2-2x)^2-2x(2-x)+1(因式分解)2.已知m^2+n^2-6m+10n+34=0,求m,n的值注x^y就是x的y次方.

Question

1.(x^2-2x)^2-2x(2-x)+1 (因式分解)
2.已知m^2+n^2-6m+10n+34=0,求m,n的值
注x^y就是x的y次方.

Answer 1

1.(x^2-2x)^2-2x(2-x)+1
=(x^2-2x)^2-2(2x-x^2)+1
=(x^2-2x)^2+2(x^2-2x)+1
=(x^2-2x+1)^2
2.已知m^2+n^2-6m+10n+34=0,求m,n的值
(m^2-6m+9)+(n^2+10n+25)=0
(m-3)^2+(n+5)^2=0
m-3=0
n+5=0
m=3
n=-5