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设y=y(x)满足2y+sin(x+y)=0,求y'..
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设y=y(x)满足2y+sin(x+y)=0,求y'..
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设y=y(x)满足2y+sin(x+y)=0,求y'..
两边对x求导,得
2y'+cos(x+y)×(1+y')=0
(2+cos(x+y))y'=-cos(x+y)
y'=-cos(x+y)/(2+cos(x+y))
两边对x求导,得
2y'+cos(x+y)×(1+y')=0
(2+cos(x+y))y'=-cos(x+y)
y'=-cos(x+y)/(2+cos(x+y))
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