-3(2s-5)+6s;1-(2a-1)-(3a+3);3(-ab+2a)-(3a-b); 14(abc-2a)+3(6a-2abc) ;-4(pq+pr)+(4pq+pr)

Question

-3(2s-5)+6s;1-(2a-1)-(3a+3);3(-ab+2a)-(3a-b); 14(abc-2a)+3(6a-2abc) ;-4(pq+pr)+(4pq+pr)

Answer 1

-3(2s-5)+6s
=-6s+15+6s
=(-6s+6s)+15
=0+15
=15
1-(2a-1)-(3a+3)
=1-2a+1-3a-3
=(1+1-3)+(-2a-3a)
= -1-5a
3(-ab+2a)-(3a-b)
=-3ab+6a-3a+b
=-3ab+(6a-3a)+b
=-3ab+3a+b
14(abc-2a)+3(6a-2abc)
=14abc-28a+18a-6abc
=(14abc-6abc)+(-28a+18a)
=8abc-10a
-4(pq+pr)+(4pq+pr)
=-4pq-4pr+4pq+pr
=(-4pq+4pq)+(-4pr+pr)
=0-3pr
= -3pr