数学题啊已知|ab-2|与|b-1|互为相反数试求代数式ab/1+(a+1)(b+1)/1+(a+2)(b+2)/1+(a+3)(b+3)/1+..+(a+2004)(b+2004)/1的值kuaikuai!!!!!!!!!!!!!!!

Question

数学题啊
已知|ab-2|与|b-1|互为相反数试求代数式ab/1+(a+1)(b+1)/1+(a+2)(b+2)/1+(a+3)(b+3)/1+..+(a+2004)(b+2004)/1的值
kuaikuai !!!!!!!!!!!!!!!

Answer 1

已知|ab-2|与|b-1|互为相反数,试求 1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+……+1/（a+2003）（b+2003） +1/(a+2004)(b+2004)因为|ab-2]+|b-1|=0 所以：ab-2=0,b-1=0 b=1 a=2 原式=1/1*2+1/2*3+1/3*4+.+1/2004*2005+1/2005...