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sin(a+π/3)+2sin(a-π/3)-根号3cos(2π/3-a)

题目详情
sin(a+π/3)+2sin(a-π/3)-根号3cos(2π/3-a)
▼优质解答
答案和解析
sin(a+π/3)+2sin(a-π/3)-根号3cos(2π/3-a)
=sinacosπ/3+cosasinπ/3+2sinacosπ/3-2cosasinπ/3-√3cosacos2π/3-√3sinasin2π/3
=sina*1/2+cosa*√3/2+2sina*1/2-2cosa*√3/2-√3cosa*(-1/2)-√3sina*√3/2
=-√3cosa