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3tan(a-π/12)=tan(a+π/12)求a
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3tan(a-π/12)=tan(a+π/12) 求a
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答案和解析
3tan(a-π/12)=tan(a+π/12)
3sin(a-π/12)cos(a+π/12)=sin(a+π/12)cos(a-π/12)
3[sin2a-sin(π/6)]=sin2a+sin(π/6)
2sin2a=4sin(π/6)=4*(1/2)=2
sin2a=1
2a=2kπ+π/2
a=kπ+π/4 (k∈Z)
3sin(a-π/12)cos(a+π/12)=sin(a+π/12)cos(a-π/12)
3[sin2a-sin(π/6)]=sin2a+sin(π/6)
2sin2a=4sin(π/6)=4*(1/2)=2
sin2a=1
2a=2kπ+π/2
a=kπ+π/4 (k∈Z)
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