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[tan(2π-α)·sin(2π-α)·cos(6π-α)·sin(3π/2-α)]/[cos(-α)·sin(5π+α)·cos(3π/2-α)·sin(α-π)]

题目详情
[tan(2π-α)·sin(2π-α)·cos(6π-α)·sin(3π/2 -α)]/[cos(-α)·sin(5π+α)·cos(3π/2 -α)·sin(α-π)]
▼优质解答
答案和解析
=-tanα*(-sinα)*cosα*sinα*(-cosα)/cosα*(-sinα)*(-sinα)*(-sinα)=-1