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已知x/2=y/3=z/4,且x+y-z=1/12,求x,y,z
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已知x/2=y/3=z/4,且x+y-z=1/12,求x,y,z
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答案和解析
x/2=y/3=z/4=k
x=2k,y=3k,z=4k
x+y-z=1/12
即 2k+3k-4k=1/12
k=1/12
x=1/6
y=1/4
z=1/3
x=2k,y=3k,z=4k
x+y-z=1/12
即 2k+3k-4k=1/12
k=1/12
x=1/6
y=1/4
z=1/3
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