已知：x/2=y/3=z/4,求（x2+y2-z2-2xy）/（x2-y2+z2-2xz）除以（x2-y2-z2+2yz)/(x2+y2-z2+2xy)

Question

已知：x/2=y/3=z/4,求（x2+y2-z2-2xy）/（x2-y2+z2-2xz）除以（x2-y2-z2+2yz)/(x2+y2-z2+2xy)

Answer 1

设 x/2=y/3=z/4 = k
则 x = 2k,y=3k,z=4k,代入你要的式子就可以算出结果,因为式子中都是2次方,最后k可以消掉.